Prob. 34: Dos soluciones distintas NOP S0 0 0 XS XS 1 CONT← 0 / C ←A CL / WC, RA D←B WD, RB 1 CONT← 0 / C ←A CL / WC, RA S1 D←B WD, RB S2 S3 0 C←A WC, RA E<F 1 0 S4 B←C WB, RC S5 C ← SHL(C, X) / D ← SHL(D, X) / CONT←CONT + 1 SLC / SLD / UP FIN SF S4 A←B WA, RB S5 B←C WB, RC S6 0 0 CY 1 FIN a S0 Dpto. Tecnología Electrónica C←A WC, RA E<F S3 1 E>F 1 A←B WA, RB S2 0 0 CY S1 C ← SHL(C, X) / D ← SHL(D, X) / CONT←CONT + 1 SLC / SLD / UP 1 E>F 1 S0 NOP SF a S0 EC Boletín Sistemas Digitales y Computadores a nivel RT Prob. 34: Productos Controlador PLA S: Q2Q1Q0 = D2D1D0 Producto (Pi) activará a ... S0: NOP 0 P0 = XSq2q1q0 XS 1 CONT← 0 / C ←A CL / WC, RA P1 = q2q1q0 CL, WC, RA, D1 D←B WD, RB P2 = q2q1q0 WD, RB, D1,D0 000 S1: S2: D0 001 010 S3: 0 1 E>F P4 1 P3 = (E>F) q2q1q0 D2,D1 0 E<F C←A WC, RA 0 CY P5 1 P6 P7 A←B WA, RB S4: 100 B←C WB, RC S5: 101 011 C ← SHL(C, X) / D ← SHL(D, X) / CONT←CONT + 1 SLC / SLD / UP P8 P9 FIN SF: 110 a S0 P4 = (E>F) (E<F) q2q1q0 WC, RA, D2 P5 = (E>F) (E<F) CY q2q1q0 P6 = q2q1q0 WA, RB, D2, D0 P8 = (E>F) (E<F) CY q2q1q0 P9 = q2q1q0 SLC, SLD, UP, D1, D0 P7 = q2q1q0 WA, RB, D2, D1 D2, D1 FIN Dpto. Tecnología Electrónica EC Boletín Sist. Dig. y Comput. nivel RT Prob. 34: Controlador PLA P0 P2 P4 P6 P8 P1 P3 P5 P7 P9 Dpto. Tecnología Electrónica EC Boletín Sistemas Digitales y Computadores a nivel RT